Question

if the loudness of a sound is reduced do 36%,then the amplitude get reduced to​

Answer 1

Given : loudness of a sound is reduced to 36%

To find : amplitude gets reduced to

Solution:

Loudness is directly proportional to square of the amplitude.

Loudness ∝ (Amplitude)²

=> Loudness = k (Amplitude)²  

Let say loudness = L

Amplitude =  A

L  = k A²

loudness of a sound is reduced to 36%

=> new loudness Lₙ = 0.36L

Lₙ = k ( Aₙ)²

=> 0.36L = k ( Aₙ)²

=> 0.36 k A² = k ( Aₙ)²

=> ( Aₙ)² = 0.36A²

=> ( Aₙ)² =(0.6A)²

=> Aₙ = 0.6A

Amplitude get reduced to 60 %

Answer 2

Answer:

(*❛‿❛)→Amplitude get reduced to 60 %

Explanation:

☞Given :

loudness of a sound is reduced to 36%

☞To find :

amplitude gets reduced to

☞Solution:

Loudness is directly proportional to square of the amplitude.

Loudness ∝ (Amplitude)²

=> Loudness = k (Amplitude)²

Let say loudness = L

Amplitude = A

L = k A²

loudness of a sound is reduced to 36%

=> new loudness Lₙ = 0.36L

Lₙ = k ( Aₙ)²

=> 0.36L = k ( Aₙ)²

=> 0.36 k A² = k ( Aₙ)²

=> ( Aₙ)² = 0.36A²

=> ( Aₙ)² =(0.6A)²

=> Aₙ = 0.6A

☞Amplitude get reduced to 60 %