Question

if sinA =3/5 then sin2A =​

Answer 1

You need to apply the double angle formula for the sine:

sin(2A) = 2sin(A)cos(A)

Since sin(A) = 3/5:

sin(2A) = 2*(4/5)*cos(A) = (8/5)cos(A)

To find cos(A), use the Pythagorean identity:

sin2(A) + cos2(A) = 1

cos2(A) = 1 - sin2(A)

cos2(A) = 1 - (4/5)2

cos2(a) = 9/25

√cos2(A) = √(9/25)

cos(A) = ±3/5

So:

sin(2A) = (8/5)*(±3/5) = ±24/25

this is just example just by yourself

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Answer 2

$\huge{\underline{\bf\red{QuestiØn} :}}$

$\sf If \: \boxed{\sin A = \frac{3}{5}} \: then \: find \: \boxed{ \sin2A}.$

$\huge{\underline{\bf\blue{SolutiØn}\ :}}$

It's given that :

• $\sin A = \dfrac{3}{5}$

Therefore,

• $\cos A = \dfrac{4}{5}$

Now,

$\begin{aligned} \\ \sin(2A) & = 2 \sin(A) \cos(A) \\ \\ & = 2 \times \bigg[ \frac{3}{5} \bigg] \times \bigg[ \frac{4}{5} \bigg] \\ \\ & = \frac{2 \times 3 \times 4}{5 \times 5} \\ \\ & = \boxed{ \bf \ \ \frac{24}{25} \ \ } & & & & & & \end{aligned}$

$\red{\rule{5.5cm}{0.02cm}}$

$\Large{ \mid {\underline{\underline{\bf\green{BrainLiest \ AnswEr}}}} \mid }$