Question

If sinA=3 then find cscA

Answer 1

SinA=P/H=3/1
H^2=P^2+B^2
1^2=3^2+B^2
B^2=9-1
B^2=8
B=Root 8

CosecA=H/P=1/3

Answer 2

1/3
As it is the reciprocal of 3
CosecA=1/SinA