If sinA=3 then find cscA
singhavi667:
it will be 1/3
Answers
Answered by
1
SinA=P/H=3/1
H^2=P^2+B^2
1^2=3^2+B^2
B^2=9-1
B^2=8
B=Root 8
CosecA=H/P=1/3
H^2=P^2+B^2
1^2=3^2+B^2
B^2=9-1
B^2=8
B=Root 8
CosecA=H/P=1/3
Answered by
2
1/3
As it is the reciprocal of 3
CosecA=1/SinA
As it is the reciprocal of 3
CosecA=1/SinA
Similar questions
English,
10 months ago
Science,
10 months ago
History,
1 year ago
Physics,
1 year ago
Social Sciences,
1 year ago