In the given figure, DE =3/4 BC, DE I I BC and the distance between DE and BC is 3 units. If BC = 6units, What is the area of triangle BCE?
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ans is 9 cm
in bce ,. area=bh/2=6(bc)*3(db)/2 =18/2 =9cm
Hope this helps plz give brainiest
in bce ,. area=bh/2=6(bc)*3(db)/2 =18/2 =9cm
Hope this helps plz give brainiest
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