If SinA=4/5 find the value of Sin2A and Cos2A
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Answer:
Sin A = 4/5
Cos A = 3/5 [ You can check it by Pythagoras theorm ]
Sin 2A
= 2sinAcosA
= 2 × 4/5 × 3/5
= 24/25
Cos 2A
= cos^2 A - Sin^2 A
= (3/5) ^2 - (4/5)^2
= 9/25 + 16/25
= 25/25
= 1
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