Question

:
If sinA=4/5 find the value of tan 2A and sin3A
​

Answer 1

Answer:

Given, sinA=

5

3

=

h

p

∴b=

25−9

=

16

=4

secA=

b

h

=

4

5

,

tanA=

b

p

=

4

3

Therefore, sec

2

A−tan

2

A=(

4

5

)

2

−(

4

3

)

2

=

16

25

−

16

9

=

16

16

=1