If sinA = 4/5, then what is the value of A?
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Answered by
8
sinA = 4/5
A = nπ + (-1)ⁿ sin-¹(4/5)
where n is integer
A = nπ + (-1)ⁿ sin-¹(4/5)
where n is integer
Answered by
6
A can be represented as A=sin⁻1(4/5) =cos⁻1(3/5)=tan⁻1(4/3)≈63°
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