Math, asked by Shanaira8062, 11 months ago

If sinA = 9/41, compute cos A and tan A.

Answers

Answered by Anonymous
1

Answer:

ıllıllı ђєץคค ๓คՇє ❗ ıllıllı

Step-by-step explanation:

▓█►─═ ʀᴇꜰᴇʀ ᴛʜᴇ ᴀᴛᴛᴀᴄʜᴇᴅ ᴘɪᴄᴛᴜʀᴇ ═─◄█▓

ツツ ђ๏קє ย ɭเкє เՇ ツツ

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Answered by nargisalware786
1

Answer: we know that,

sinA2+ cosA2 = 1

(9/41)2 + cosA2 = 1

cosA2 = 1 - 81/1681

cosA2 = 1681 - 81/1681

cosA2 = 1600/1681

Taking square root

cosA = 40/41

tanA = sinA/ cosA

tanA = 9/41 ÷ 40/41

tanA = 9/41 × 41/40

Therefore, tanA = 9/40

Step-by-step explanation: by trinometry

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