If sinA = 9/41, compute cos A and tan A.
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ツツ ђ๏קє ย ɭเкє เՇ ツツ
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Answer: we know that,
sinA2+ cosA2 = 1
(9/41)2 + cosA2 = 1
cosA2 = 1 - 81/1681
cosA2 = 1681 - 81/1681
cosA2 = 1600/1681
Taking square root
cosA = 40/41
tanA = sinA/ cosA
tanA = 9/41 ÷ 40/41
tanA = 9/41 × 41/40
Therefore, tanA = 9/40
Step-by-step explanation: by trinometry
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