Question

if sinA-cosA =1/root of 2, then 1/sinA+cosA=​

Answer 1

Step-by-step explanation:

here is your answer and once try to solve it yourself

Answer 2

Given that sin(A) - cos(A) = 1/2(This should be the equation)

Square both sides, you get

(sin(A) - cos(A))^2 = 1/4

sin^2(A) + cos^(A) - 2sin(A)cos(A) = 1/4

Sin^2(A) + cos^2(A) = 1.

Substituting in above equation

2Sin(A)Cos(A) = 1 - 1/4 = 3/4

Now Take the equation

(Sin(A) + Cos(A))^2 = sin^2(A) + cos^(A) + 2sin(A)cos(A)

= 1 + 2Sin(A)Cos(A) = 1 + 3/4 = 7/4

Apply square root both sides, you get

Sin(A) + Cos(A) = √7/2

Hence 1/(Sin(A) + Cos(A)) = 2/√7

Hope it helps

Mark it as BRAINLIEST if you are satisfied with the answer