Question

if sinA- cosA=1 then sinAcosA=​

Answer 1

Answer:

Step-by-step explanation:

(sin a-cos a)^2=1^2

sin^2a+cos^2a-2cosasina=1

sinacos=0

Answer 2

Answer:

Step-by-step explanation:

SinA-cosA=1

Squaring both sides,

(SinA-cosA)²=1²

sin²A+cos²A-2sinAcosA=1

[bcoz (a-b)²= a²+b²-2ab]

Solving, we get

1-2sinAcosA=1

(sin²A+cos²A=1)

-2sinAcosA=0

sinAcosA=0