If sinA=cosB=√3/2.find tha value of tanA-tanB/1-tanA.tanB
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sinA = root3/2
A = pi/3
cosB = root3/2
B = pi/6
tanA = root 3
tanB = 1/(root3)
Therefore the value of above equation is
(root3 - 1/(root3))/(1-root3×(1/root3))
= (2/0)
= Not defined
A = pi/3
cosB = root3/2
B = pi/6
tanA = root 3
tanB = 1/(root3)
Therefore the value of above equation is
(root3 - 1/(root3))/(1-root3×(1/root3))
= (2/0)
= Not defined
Astrobolt:
Either my answer is correct or in the question the tan part should be '+' in the denominator
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