If sinA + cosec A = 2, then sin^2 + cosec ^2 =?
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Given:
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SinA + CosecA = 2
Squaring on both sides, we get
(SinA + CosecA)^2 = 4
Sin^2A + Cosec^2A + 2*SinA*CosecA = 4
Sin^2A + Cosec^2A + 2 = 4 [Since SinA*CosecA =1]
Sin^2A + Cosec^2A = 4 - 2
Sin^2A + Cosec^2A = 2 ——> Answer
———
SinA + CosecA = 2
Squaring on both sides, we get
(SinA + CosecA)^2 = 4
Sin^2A + Cosec^2A + 2*SinA*CosecA = 4
Sin^2A + Cosec^2A + 2 = 4 [Since SinA*CosecA =1]
Sin^2A + Cosec^2A = 4 - 2
Sin^2A + Cosec^2A = 2 ——> Answer
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