Math, asked by sujalpandey2063, 7 months ago

If sinA + cosecA=3, find the value of sin^2A+cosec^A

Answers

Answered by manishkumag06
6

Answer:

7

Step-by-step explanation:

sinA + cosecA=3

Squaring both side

(sinA+cosecA)^{2} = 3^{2}

user formula (a+b)^{2} = a^{2}  + 2ab + b^{2}

sin^{2}A + 2*sinA * cosecA + cosec^{2} A = 9

sin^{2}A + 2*1 + cosec^{2} A = 9

sin^{2}A + cosec^{2}A = 9 -2\\sin^{2}A + cosec^{2}A = 7

Answered by aiyshanizar792
6

Answer:

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