Math, asked by sheoransahil002, 1 day ago

If sinA is 1/3 ,the value of (9vot^2A+9 ) is​

Answers

Answered by raj333162
1

Answer:

Step-by-step explanation:

sinA = 1/3

sin^2A + cos^2A = 1

cos^2A = 1 - sin^2A

            = 1 - (1/3)^2 = 1 - 1/9  = 8/9

cosA = 2\sqrt{2}/3

cot^2A = cos^2A/sin^2A

           = 8/9 / 1/9

           = 8

so 9cot^2A + 9 = 9(8) + 9

                         = 72 + 9

                         =81

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