If sinA is 1/3 ,the value of (9vot^2A+9 ) is
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Answer:
Step-by-step explanation:
sinA = 1/3
sin^2A + cos^2A = 1
cos^2A = 1 - sin^2A
= 1 - (1/3)^2 = 1 - 1/9 = 8/9
cosA = 2/3
cot^2A = cos^2A/sin^2A
= 8/9 / 1/9
= 8
so 9cot^2A + 9 = 9(8) + 9
= 72 + 9
=81
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