Question

If sinA=m/n , find tanA+4/4cotA+1​

Answer 1

Answer:

If sinA = m/n,

cosA=√{n²-m²}/n

as base is √{n²-m²}

now, tanA= m/√{n²-m²}

and cotA=√{n²-m²}/m

so tanA+4/4cotA+1

= m+4(√{n²-m²})/√{n²-m²} / 4√{n²-m²}+m/m

and find the answer