Question

if sina=root3/2 and cosB=0 then A-B​

Answer 1

Answer:

A = 60°

B = 90°

A - B = - 30° .......

Answer 2

The value of A - B​ = - 30°

Step-by-step explanation:

We have,

$\sin A=\dfrac{\sqrt{3}}{2}$ and $\cos B=0$

To find, the value of A - B​ = ?

∴$\sin A=\dfrac{\sqrt{3}}{2}$

⇒ $\sin A=\sin 60$ [ ∵ $\sin 60=\dfrac{\sqrt{3}}{2}$]

⇒ A = 60°

Also,

$\cos B=0$

⇒ $\cos B=\cos 90$

⇒ B = 90°

∴ A = 60° and B = 90°

∴ A - B = 60° - 90°

=  - 30°

Hence, the value of A - B​ =  - 30°