Question

if sinA+ sin B+sinC=3 then cos A+cosB+ cos c= ______ a)3 b)2 c)1 d)0​

Answer 1

Answer:

I Dought option a and c

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Answer 2

Answer:

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Step-by-step explanation:

sinA+sinB+sinB=1+1+1

or. (sinA-1)+(sinB-1)+(sinC-1)=0………..(1)

Comparing the both sides of eqn. (1)

(sinA-1)=0. => sinA= 1 or A=90°

(sinB-1)=0 => sinB=1 or B=90°

(sinC-1)=0. => sinC=1 or C=90°.

Now cosA+cosB+cosC=?

Putting. A=B=C=90°

=cos90°+cos90°+cos90°

=0+0+0

= 0