if sinA +Sin square A =1, then find the value of cos square A + cos power 4 A
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ᴇʟʟᴏ!!
ʜᴇʀᴇ's ʏᴏᴜʀ ᴀɴsᴡᴇʀ
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ɢɪᴠᴇɴ , sɪɴ ᴀ + sɪɴ^2 ᴀ = 1
ᴛᴏ ғɪɴᴅ ᴛʜᴇ ᴠᴀʟᴜᴇ ᴏғ ᴄᴏs^2 ᴀ + ᴄᴏs^4 ᴀ
ɴᴏᴡ ,
sɪɴ ᴀ + sɪɴ^2 ᴀ = 1
=> sɪɴ ᴀ = 1 - sɪɴ^2 ᴀ
=> sɪɴ ᴀ = ᴄᴏs^2 ᴀ
=> ( sɪɴ ᴀ )^2 = ( ᴄᴏs^2 ᴀ )^2
=> sɪɴ^2 ᴀ = ᴄᴏs^4 ᴀ
=> 1 - ᴄᴏs^2 ᴀ = ᴄᴏs^4 ᴀ
=> - ᴄᴏs^2 ᴀ - ᴄᴏs^4 ᴀ = - 1
=> - ( ᴄᴏs^2 ᴀ + ᴄᴏs^4 ᴀ ) = - 1
=> ᴄᴏs^2 ᴀ + ᴄᴏs^4 ᴀ = 1
sᴏ , ᴛʜᴇ ᴠᴀʟᴜᴇ ᴏғ ( ᴄᴏs^2 ᴀ + ᴄᴏs^4 ᴀ ) ɪs 1
____________________________
ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs ʏᴏᴜ ᴅᴇᴀʀ!
★ ᴅᴇᴠɪʟ ᴋɪɴɢ
ʜᴇʀᴇ's ʏᴏᴜʀ ᴀɴsᴡᴇʀ
_________________________
ɢɪᴠᴇɴ , sɪɴ ᴀ + sɪɴ^2 ᴀ = 1
ᴛᴏ ғɪɴᴅ ᴛʜᴇ ᴠᴀʟᴜᴇ ᴏғ ᴄᴏs^2 ᴀ + ᴄᴏs^4 ᴀ
ɴᴏᴡ ,
sɪɴ ᴀ + sɪɴ^2 ᴀ = 1
=> sɪɴ ᴀ = 1 - sɪɴ^2 ᴀ
=> sɪɴ ᴀ = ᴄᴏs^2 ᴀ
=> ( sɪɴ ᴀ )^2 = ( ᴄᴏs^2 ᴀ )^2
=> sɪɴ^2 ᴀ = ᴄᴏs^4 ᴀ
=> 1 - ᴄᴏs^2 ᴀ = ᴄᴏs^4 ᴀ
=> - ᴄᴏs^2 ᴀ - ᴄᴏs^4 ᴀ = - 1
=> - ( ᴄᴏs^2 ᴀ + ᴄᴏs^4 ᴀ ) = - 1
=> ᴄᴏs^2 ᴀ + ᴄᴏs^4 ᴀ = 1
sᴏ , ᴛʜᴇ ᴠᴀʟᴜᴇ ᴏғ ( ᴄᴏs^2 ᴀ + ᴄᴏs^4 ᴀ ) ɪs 1
____________________________
ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs ʏᴏᴜ ᴅᴇᴀʀ!
★ ᴅᴇᴠɪʟ ᴋɪɴɢ
Answered by
13
Here is the answer mate!!
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