find two consecutive positive even numbers such that the sum of their squares is equal to 164
Answers
Answered by
35
let one of the no be x
then other will be x+2
ATQ
(x)sq + (x+1) = 164
(x)sq + (x)sq + 2x + 1 = 164
on solving it further we will get
x=8
and,
x+2=10
hence the 2 no’s are 8 and 10
hope it will help you : )
then other will be x+2
ATQ
(x)sq + (x+1) = 164
(x)sq + (x)sq + 2x + 1 = 164
on solving it further we will get
x=8
and,
x+2=10
hence the 2 no’s are 8 and 10
hope it will help you : )
Answered by
8
The two consecutive integer are 8 and 10
You can find the answer by this equation
(x^2)+(x+1)^2=164
From this equation your answer will be 8 and 10
And the square of 8 and 10 is 64 and 100 respectively
And the sum is 164
You can find the answer by this equation
(x^2)+(x+1)^2=164
From this equation your answer will be 8 and 10
And the square of 8 and 10 is 64 and 100 respectively
And the sum is 164
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