Question

if sinA+sin2A=1 find the value of cos12A+3cos10A+3cos8A+cos6A+2cos4A+2cos2A-2 from RD examples

Answer 1

HEY MATE_____>

HERE IS YOUR ANSWER_____!!!


If sinA + sin2A =1, then the value of cos12A + 3cos10A + 3cos8A + cos6A + 2cos4A + 2cos2A - 2 is = Math Introduction ...

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Answer 2

Dear student,

cos12 a +3cos 10a+3cos 8a+cos 6a-1

can be written as [cos^2 a + cos^4 a]^3 - 1

from given equation sin^2 a  = 1 - sin a => cos^2 a = sin a

=> [ sina a + sin^2 a ]^3 - 1  

=> 1^3 - 1

=> 0

hope it explains !!