root 3 X square + 2 root 2 x minus 2 root 3 is equal to zero
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Answered by
53
Ist approach:-
√3x²+2√2x-2√3=0,
√3x²+(3√2-√2)x-2√3=0,
√3x²+3√2x-√2x-2√3=0,
√3x(x+√6)-√2(x+√6)=0,
(x+√6)(√3x-√2)=0,
IInd approach:-
√3x²+2√2x-2√3=0,
divide by √3 in both the sides, we have
x²+2√2x/√3 - 2=0,
x²+2√2x/√3 =2,
x²+2×x×√2/√3 + (√2/√3)²=2+(√2/√3)²,
(x+√2/√3)²=2+2/3
(x+√2/√3)²=8/3
then
(x+√2/√3)=±(2√2/√3),
(x+√2/√3)=±(2√2/3),
taking +ve sign, we have
x+√2/√3 = 2√2/√3,
then
x=2√2/√3 - √2/√3,
then
x=√2/√3,
(√3x-√2)=0,
now taking -ve sign, we have
(x+√2/√3) = -2√2/√3,
then
x=-2√2/√3 - √2/√3,
x=-3√2/√3,
x=-√3/√2,
√2x+√3=0,
You can also solve it with the help of quadratic formula
√3x²+2√2x-2√3=0,
√3x²+(3√2-√2)x-2√3=0,
√3x²+3√2x-√2x-2√3=0,
√3x(x+√6)-√2(x+√6)=0,
(x+√6)(√3x-√2)=0,
IInd approach:-
√3x²+2√2x-2√3=0,
divide by √3 in both the sides, we have
x²+2√2x/√3 - 2=0,
x²+2√2x/√3 =2,
x²+2×x×√2/√3 + (√2/√3)²=2+(√2/√3)²,
(x+√2/√3)²=2+2/3
(x+√2/√3)²=8/3
then
(x+√2/√3)=±(2√2/√3),
(x+√2/√3)=±(2√2/3),
taking +ve sign, we have
x+√2/√3 = 2√2/√3,
then
x=2√2/√3 - √2/√3,
then
x=√2/√3,
(√3x-√2)=0,
now taking -ve sign, we have
(x+√2/√3) = -2√2/√3,
then
x=-2√2/√3 - √2/√3,
x=-3√2/√3,
x=-√3/√2,
√2x+√3=0,
You can also solve it with the help of quadratic formula
archit82:
thanks so much for answering
Answered by
64
I hope this will help u
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