If sinA =x, then what is the value of tan A
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tanA=sinA/cosA
= sinA/√1-sin^2A
= x/√1-x^2
= sinA/√1-sin^2A
= x/√1-x^2
ashika4:
Thanks
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SIN[tex] SIN^{2}A + COS^{2}A=1
COS^{2}A=1-SIN^{2}A
COS A= \sqrt{1-SIN^{2}A}
[/tex][tex]SIN A=X
TAN A=X/ \sqrt{1- X^{2} } [/tex]
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