Question

if sinB = 1/5 sin (2A+B), then tan(A+B)/tanA is equal to​

Answer 1

Step-by-step explanation:

sinB=

5

sin(2A+B)

⇒

sinB

sin(2A+B)

=

1

5

Using componendo and dividendo, we get

sin(2A+B)−sinB

sin(2A+B)+sinB

=

5−1

5+1

⇒

2cos(A+B)sinA

2sin(A+B)cosA

=

2

6

⇒

tanA

tan(A+B)

=

2

3