Question

if since a 3/4 then show that cos A+ since √7/2​

Answer 1

Step-by-step explanation:

sinA=3/4 then by applying the formula hyp^2= side^2+side^2 we get cosA=sq.7/4

cosA+ sinA= 3/4+sq.7/4

= 3+sq.7/4

= sq.7/2..

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Answer 2

$\huge\boxed{\fcolorbox{black}{pink}{ANSWER..}}$

Given,

∠B = 90°

Sin A = 3/4

Sin A = 3/4 = P/h = BC/AC

BC = 3

AC = 4

AB = √AC² - BC²

AB = √16 - 9

AB = √7

LHS = Cos A + Sin C

= √7/4 + √7/4

= √7 + √7/ 4

= 2√7/4

= √7/2 = RHS

•●○ Hence Proved ○●•