Question

If sine + cose= p and
sece+coseco = q, show that q (p2-1) = 2p​

Answer 1

Hlw

here is ur ans. a

Question :-

If sine + cose= p and

If sine + cose= p andsece+coseco = q, show that q (p2-1) = 2p

Answer :-

$lhs \:$

$= q(p {}^{2} - 1)$

$= ( \sec \: theta \: + \csc( \: theta) ) (( \sin \: \: theta + \: cos \: theta) {}^{2} - 1)$

$= (1 \div cos \: theta + 1 \div sin \: theta)( {sin}^{2} teta \: + {cos}^{2} theta \: + 2sin \: theta \: cs \: theta \: - 1)$

$= (sin \: theta \: + cos \: theta \div sin \: cos \: theta) \: (2sin \: theta \: cos \: theta)$

$= 2(sin \: theta \: + cos \: theta)$

$= 2p$

$= rhs$

Hence proved.

PLS MARK @achsahmajay7633 Ans as brainlist.

#Miya☺❤❤