Math, asked by akashsursh2710, 1 day ago

If Sinha's present age is x

a) what is her age 4years ago
b)Sinha's mother's age is 3 times sinhas age. what is her mother's age?


step by step explain plss​

Answers

Answered by TeacherX
2

Step-by-step explanation:

sinhas present age = x

sinhas age 4 years ago = x-4

sinhas mothers age = 3x

Answered by someshsahoo70
0

Answer:

a : x-4

b : 3x

Step-by-step explanation:

As per the question,Sinha's age is 'x' years.

And her mother's age is 3 times of Sinha's age.

So,4 years ago her age should be = 'Sinha's age-4' years

='x-4' years(Ans.)

And her mother's age should be='Sinha's age×3' years

=x•3 years ( • represents the multiple method )

=3x years(Ans.)

Similar questions