if sino-√3coso, find the value of tano-1/tano+1
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Answered by
5
Answer:
sin0-√3cos0
0-√3
√3
find the value
tan0 -1/1+tan0
=tan0+tan45/1+tan45tan0
=tan(0-45)
=-tan45
= -1
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Answered by
0
let sin0 - √3cos0 = 0
sin 0 = √3cos 0
tan0 -1/ tan 0 +1 =( sin0 /cos0) -1/ (sin0/cos0) +1
=> sin0 -cos0/ cos0 / sin0 +cos0/ cos0
sin0-cos0/sin0 +cos0
substituting th value of sin0,
✓3cos0 -cos0 / √3cos0 + cos0
squaring,
3cos0 + cos²0 - 2cos0√3 / 3cos0 +cos²0 + 2cos0√3
cancelling the common
terms,
we get,
-2cos0√3/ 2cos0√3 = -1
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