Question

if sinÒ-cosÓ=0 then the value of (sin^4Ó-cos^4Ó​

Answer 1

Step-by-step explanation:

sino-coso=0

sino=coso

sino=sin(90-o)

equate both sides

o=90-o

o+o=90

2o=90

o=90/2

o=45

now

sin^4o - cos^4o

sin(45)^4 -cos(45)^4

(1/root2)^4 -(1/root2)^4

(1/4)-(1/4)

=0 is answer