Math, asked by swatibaliyan321, 1 year ago

If sinø + cosø =√3, Find the value of tanø + cotø

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Answered by manasiriya2003
2

Answer

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Answered by paarth232
1

Hey mate here is your answer,

SinA + cosA = √3

Squaring on both sides we get,

(SinA + cosA)² = (√3)²

Sin²A + cos²A +2sinAcosA = 3

1 + 2sinAcosA = 3

2sinAcosA = 3-1

SinAcosA = 2/2

sinAcosA = 1......................(!)

tanA+cotA = 1

sinA/cosA + cosA/sinA = 1

sin²A + cos²A /sinAcosA = 1

1/sinAcosA = 1

sinAcosA = 1.....................(ii)

From i) and ii)

Thus, tanA + cotA = 1

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