Question

if sinQ=21/29 evaluate secQ/tanQ-sinQ​

Answer 1

I hope this helps you .

Formulas used,

$\sec( \alpha ) = \frac{1}{ \cos( \alpha ) } \\ \tan( \alpha ) = \frac{ \sin( \alpha ) }{ \cos( \alpha ) }$

Answer 2

Hola mate ❤❤

Here is your answer :

sinQ = 21/29 = P/H

By the Pythagoras theorem,

H^2 = P^2 + B^2

(29)^2 =( 21)^2 + B^2

841 =441+b^2

841-441=B^2

√400 =B

20 =B

therefore ,

secQ =H/B = 29/20

tanQ = P/B = 21/20

then,

secQ/tanQ -sinQ = 29/21 - 21/29 = 400/609

Hope it may help you