if sinQ+sin²Q=1 then cos²Q+cos⁴Q =?
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Answer:
cos²Q+cos⁴Q=1
Step-by-step explanation:
taking rhs
(cos²Q=1-sin²Q)
1-sin²Q+(cos²Q)²
1-(1-sinQ)+(1-sin²Q)²
1-1+sinQ+(1-(1-sinQ))²
sinQ+(1-1+sinQ)²
sinQ+sin²Q
=1
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