Question

if sinthitha=3/4,show that√cosec2thitha-cot2thitha/sec2thitha-1=√7/3?​

Answer 1

Answer:

Step-by-step explanation:

Sin = 3/4 = p/h

P=3k , h=4k (K is constant)

H²=p²+b²

B²=h²-p²

B²=(4k)²-(3k)²

B²=16k²-9k²

B²=7k²

B=/7k

/cosec²-cot²÷sec²-1 =/7÷3

=/(1)² / (tan) ²

=1÷tan

=cot

Cot =b/p

=/7÷3

Lhs = rhs

Hope it works

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Answer 2

Answer:

Step-by-step explanation: see attachement