Question

If sinX =30 and
secX=1/30 then
find the value of
tanX.​

Answer 1

Answer: 1

Given:

$\large\sf sinx = 30$

$\large\sf sec x=\frac{1}{30}$

To find:

$\large\sf tanx$

Explanation:

$\sf\text{We know that,}$

$\large \sf sinx=\frac{Perpendicular(P)}{Hypotenuse(H)}$

$\large \sf secx=\frac{1}{cosx}=\frac{Hypotenuse(H)}{Base(B)}$

$\large\sf tanx=\frac{Perpendicular(P)}{Base(B)}$

$\sf\text{According to the question,}$

$\large\sf sinx=\frac{30}{1}=\frac{P}{H}$

$\large\sf secx=\frac{1}{30} =\frac{H}{B}$

$\large\sf tanx=\frac{P}{B}=\frac{30}{30}=1$

$\sf\textbf{Therefore, the value of tanx is 1.}$