Question

if sinX+cosecx=2,then sin^19x+cosec^20x=​

Answer 1

Answer:

→ 2

Step-by-step explanation:

We have

→ Sin x + cosec x = 2 ( cosec x = 1/ sin x )

So ,

→ Sin x + 1/ sin x = 2

→(sin²x +1)/sinx = 2

→ Sin²x + 1 - 2sin x = 0

→ (sin x -1)²= 0

→ sin x = 1

Hence [ x = π/2 ]

,now put the value of x in required solution

Now we have ,

→( sin π/2 )^19 + (cosec π/2)^20

→ 1 + 1 = 2

Thanks.