Math, asked by SrijaAnusha, 4 months ago

if sinx+cosecx=2 then sin*8x+ cosec*8 x=

Answers

Answered by Anonymous
3

Answer:

2

Sin x+cosec x=2

Sin x + 1/sin x =2

Sin^2 x +1=2sin x

Sin^2 x -2sin x + 1 =0

(Sin x -1)^2 =0

(Sin x - 1) =0

Sin x= 1

Sin^8 x+cosec^8

= (sin x) ^8 + (1/sin x) ^8

=1^8+1^8

= 1 +1

= 2

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