Math, asked by neerajvermag11, 1 year ago

if sinx=nsin(x+2A), show that:-tan(x+A)=(1+n/1-n) tanA

Answers

Answered by wwevikash
16
Hey mate,

⚡here is your answer

⭐sin(x+2a) / sin(x) = 1/n

[sin(x+2a) + sin(x)] / [sin(x+2a) – sin(x)] = (1+n) / (1-n)

(:.Using componendo and dividendo)

2.sin(x+a).cos(a) / 2.sin(a).cos(x+a) = (1+n) / (1-n)
tan(x+a) / tan(a)

= (1+n) / (1-n)tan(x+a)

I hope it helps.
⭐mark it as brainliest.

= (1+n) × tan(a)/ (1-n)

neerajvermag11: 2.sin(x+a).cos(a) / 2.sin(a).cos(x+a) = (1+n) / (1-n)
tan(x+a) / tan(a)

= (1+n) / (1-n)tan(x+a)
neerajvermag11: tell me in detail
neerajvermag11: Prove that. Tan alpha +cotA=2cosec2A & deduce that tan75°+cot75°=4
Answered by sidwarrior123
2

Answer:

ok

Step-by-step explanation:

sinx=nsin(x+2A), show that:-tan(x+A)=(1+n/1-n) tanA

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