If Siobhan hits a 0.25 kg volleyball with 0.5 N of force, what is the acceleration of the ball?
Answers
Answer:
2N/Kg.
Explanation:
We know , force = mass x acceleration.
force = 0.5
mass = 0.25 kg.
acceleration = force / mass
= 0.5 / 0.25
= 2 N/kg.
Given,
Mass of the volleyball = m = 0.25 Kg = 250 grams
Siobhan hits the volleyball with a force = F = 0.5 N
To find,
The acceleration of the ball.
Solution,
We can simply solve this numerical problem by using the following process:
Let us assume that the acceleration of the volleyball is "a" meters per second square.
Newton's second law states that;
" The force F acting on a body is equal to the product of mass m of the body and the acceleration a of its center of mass, i.e. F = ma "
Now,
Force acting on the volleyball = mass of the volleyball x acceleration of the ball
=> F = m x a
=> 0.5 N = 0.25 kg x a
=> a = (0.5 ÷ 0.25) meters per second square
=> a = 2 meters per second square = 2 m sec^-2
Hence, the acceleration of the ball is 2 meters per second square.