Two hot-air balloons, one red and one blue, took off at the same time from different platforms. Each began ascending at a constant rate. The following equation gives the height (in meters) of the red hot-air balloon as a function of time (in seconds). h = \dfrac{1}{2} t + 4h= 2 1 t+4h, equals, start fraction, 1, divided by, 2, end fraction, t, plus, 4 The height (in meters) of the blue hot-air balloon as a function of time (in seconds) is given by the following table of values: \text{Time}Timestart text, T, i, m, e, end text (seconds) \text{Height}Heightstart text, H, e, i, g, h, t, end text (meters) 444 555 666 666 888 777 Which balloon started at a greater height? Choose 1 answer: Choose 1 answer: (Choice A) A The red one (Choice B) B The blue one (Choice C) C They both started at the same height Which balloon ascended faster? Choose 1 answer: Choose 1 answer: (Choice A) A The red one (Choice B) B The blue one (Choice C) C They both ascended at the same rate
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Answered by
5
Both Baloon started at the Same height & Blue Baloon Ascend Faster
Step-by-step explanation:
Red Ballon h = t/2 + 4
t h
0 4
1 4.5
2 5
3 5.5
4 6
Speed = 1/2 m/s
Blue Baloon
t h
0 4
1 5
2 6
3 7
4 8
Speed = 1 m/s
At t= 0 , Height of both baloon is same
Hence both Baloom started at the Same height
Blue Baloon Ascend Faster
Learn more:
What is the value of f(−1) when f(x)=2x+2
https://brainly.in/question/13189742
Answered by
11
Answer:
1. the red balloon
2.they both ascended at the same rate
Step-by-step explanation:
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