Question

If six - digit number 5x2y6z is divisible by 7, 11 and 13, then the value of (x - y + 3z) is:​

Answer 1

Answer:

We know that if a number is divisible by 7 , 11 , 13 then it is of the form

abcabc

so here 479 xyz will be equal to x = 4 , y = 7 , z = 9

value of