Math, asked by ranuprajapati567, 4 months ago

solve by transposition method 6/7x-1/7=11​

Answers

Answered by dibyangshughosh309
45

Answer:

  •  \leadsto \red{ \boxed{ \green{ \tt{x =  \bold{13}}}}}

Step-by-step explanation:

Given :

  •  \sf \frac{6}{7} x -  \frac{1}{7}  = 11

To Find :

  • the value of x

Solution :

__________________________________________

By using Transporting Method

 \\  \sf :  \implies \frac{6}{7} x -  \frac{1}{7}  = 11 \\  \\

 \\  \sf :  \implies \frac{6x}{7}  -  \frac{1}{7}  = 11 \\  \\

Transport 1/7 to the right side of the equation

  • As 1/7 is in negative state in the left side of the equation so when 1/7 will transport to the right side of the equation 1/7 will be positive State.

 \\  \sf :  \implies \frac{6x}{7}  = 11 +  \frac{1}{7}  \\  \\

 \\  \sf :  \implies \frac{6x}{7}  =  \frac{77 + 1}{7}  \\  \\

 \\  \sf :  \implies \frac{6x}{7}  =  \frac{78}{7}  \\  \\

Transport 7 to the right side of the equation

  • As 7 is in division state in the left side of the equation so when 7 will transport to the right side of the equation 7 will be in multiple state

 \\  \sf :  \implies6x =  \frac{78}{7}  \times 7 \\  \\

 \\  \sf :  \implies6x = 78 \\  \\

Transport 6 to the right side of the equation

  • As 6 is in multiple state in the left side of the equation so when 6 will transport to the right side of the equation 6 will be in division state

 \\  \sf :  \implies \: x =  \frac{78}{6}  \\  \\

 \\  \sf :  \implies \:   \boxed{\frak{ \pink{x = 13}}}\\ \\

__________________________________________

Therefore , the value of x is 13.

Answered by Thanked
15

Answer:

Answer:

\leadsto \red{ \boxed{ \green{ \tt{x = \bold{13}}}}}⇝

x=13

Step-by-step explanation:

Given :

\sf \frac{6}{7} x - \frac{1}{7} = 11

7

6

x−

7

1

=11

To Find :

the value of x

Solution :

__________________________________________

By using Transporting Method

\begin{lgathered}\\ \sf : \implies \frac{6}{7} x - \frac{1}{7} = 11 \\ \\\end{lgathered}

:⟹

7

6

x−

7

1

=11

\begin{lgathered}\\ \sf : \implies \frac{6x}{7} - \frac{1}{7} = 11 \\ \\\end{lgathered}

:⟹

7

6x

7

1

=11

Transport 1/7 to the right side of the equation

As 1/7 is in negative state in the left side of the equation so when 1/7 will transport to the right side of the equation 1/7 will be positive State.

\begin{lgathered}\\ \sf : \implies \frac{6x}{7} = 11 + \frac{1}{7} \\ \\\end{lgathered}

:⟹

7

6x

=11+

7

1

\begin{lgathered}\\ \sf : \implies \frac{6x}{7} = \frac{77 + 1}{7} \\ \\\end{lgathered}

:⟹

7

6x

=

7

77+1

\begin{lgathered}\\ \sf : \implies \frac{6x}{7} = \frac{78}{7} \\ \\\end{lgathered}

:⟹

7

6x

=

7

78

Transport 7 to the right side of the equation

As 7 is in division state in the left side of the equation so when 7 will transport to the right side of the equation 7 will be in multiple state

\begin{lgathered}\\ \sf : \implies6x = \frac{78}{7} \times 7 \\ \\\end{lgathered}

:⟹6x=

7

78

×7

\begin{lgathered}\\ \sf : \implies6x = 78 \\ \\\end{lgathered}

:⟹6x=78

Transport 6 to the right side of the equation

As 6 is in multiple state in the left side of the equation so when 6 will transport to the right side of the equation 6 will be in division state

\begin{lgathered}\\ \sf : \implies \: x = \frac{78}{6} \\ \\\end{lgathered}

:⟹x=

6

78

\begin{lgathered}\\ \sf : \implies \: \boxed{\frak{ \pink{x = 13}}}\\ \\\end{lgathered}

:⟹

x=13

__________________________________________

Therefore , the value of x is 13.

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