If six persons sit in a row, what is the probability that A and B are
sitting on adjacent seats?
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Answer:
No of ways in which 6 persons can be seated in a row = 6!
Since A & B have to be together, consider them as single unit. Now, 5 units can be seated in a row in 5! x 2! ways as A&B can be arranged in 2! ways.
Required probability is :
(5! x 2!)/6! = 1/3
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