If Sn = 3n ² + 9n then its 6th term is
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Answer:
Given Sn=3n2+5n
S1=a1=3(1)2+5(1)=3+5=8
S2=a1+a2=3(2)2+5(2)=3(4)+10=22
⇒8+a2=22
⇒a2=14
S3=a1+a2+a3=3(3)2+5(3)=27+15=42
⇒a3=S3−S2=42−22=20
d=a2−a1=a3−a2=
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