If Sn=3n²+n,find the A.P.
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Solution:-
Given Equation:-
Sn = 3n² + n
Taking ( n = 1). we get,
=) S(1) = 3 × 1² + 1
=) S(1) = 4.
Hence,
First Term = a = 4.
Taking ( n=2). we get,
=) S(2) = 3 × 2² + 2
=) S (2) = 3× 4 + 2
=) S (2) = 14.
Now,
Second Term = Sum of First two term - First Term
=) Second Term= 14 - 4
=) Second Term = 10.
To Make the Term in A.P.
We should Find out the Common Difference (D), which is always constant.
=) D = Second Term - First Term
=) D = 10 - 4
=) D = 6.
=) Common Difference = 6.
Hence,
The A.P. is 4, 10, 16, 22, 28,...........
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