if Sn denotes the sum of first n term of an ap then prove that
S12=3(s8-s4)?
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Answer:S12 = 6(2a+11d)
=12a+66d
s8=4(2a+7d)
=8a+28d
s4= 2(2a+3d)
=4a+6d
3(s8-s4)=3{(8a+28d-4a-6d})
=3{(4a+22d)
=12a+66d
=6(2a+11d)
=S12
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