If Sn denotes the sum of first n terms of AP . Prove that S30 = 3× (S20 -S10)
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Answer:
HENCE PROVED
Step-by-step explanation:
Sn=n/2(2a+n-1(d))
S30=30/2(2a+(30-1)d)
S30=15(2a+29d)--------------------------(1)
substitute S10 and S20 in expanded form
S30 = 3 (20/2(2a+(20-1)d) - (10/2(2a+(10-1)d))
=3(10 x 2a+19d) - (5 x 2a+9d)
Simplify this to get
=15(2a+29d)-------------------(2)
So, here (1) and (2) are equal
HENCE PROVED
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