IF Sn= n/n+2for a sequence {tn} then find the first three terms of {tn}
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sn =n/n+2----(1)
1)s1 =1/(1+2)=1/3
2)s2=2/(2+2)=2/4=1/2
3)s3=3/(3+2)=3/5
t1=s1=1/3
t2=s2-s1=1/2 -1/3=(3-2)/6=1/6
t3=s3-s2=3/5 -1/2 = (6-5)/10=1/10
therefore
1/3,1/6,1/10 are first three terms
1)s1 =1/(1+2)=1/3
2)s2=2/(2+2)=2/4=1/2
3)s3=3/(3+2)=3/5
t1=s1=1/3
t2=s2-s1=1/2 -1/3=(3-2)/6=1/6
t3=s3-s2=3/5 -1/2 = (6-5)/10=1/10
therefore
1/3,1/6,1/10 are first three terms
mysticd:
ur welcome
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