If Sn, the sum of first n terms of an A.P. is given by Sn = 5n2 + 3n, then find its nth term and common difference.
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S1=5×1²+3×1
=5+3
=8
S2=5×2²+3×2
=20+6
=26
2nd term= 26-8
=18
d= 18-8
=10
AP is 8,18,26,34......
=5+3
=8
S2=5×2²+3×2
=20+6
=26
2nd term= 26-8
=18
d= 18-8
=10
AP is 8,18,26,34......
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