Physics, asked by itzzzemma0301, 3 months ago

If solid S floats in a liquid L with 1/6th of its volume is submerged then density of liquid is n times the density of solid. Value of n is?

Answers

Answered by dragonsragespell
0

Answer:

6

Explanation:

density solid x volume of solid x g = density liquid x volume submerged x g

density solid x (volume solid/volume submerged) = density liquid

d solid x 6 = d liquid

so n = 6

hope it helps

sincearly,

random dude

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