Question

the condition so that the pair of linear equation kx+3y+1=0,2x+y+3 has exactly one solution​

Answer 1

Answer:

Step-by-step explanation:

compare both equations with a1x +b1y+c1=0 and a2x+b2y+c2=0

a1=k, b1=3, c1=1 and

a2=2,b2=1, c2=3

condition to they have one solution is

a1/a2 not equal to b1/b2(use not equal synmbo l)

k/2not equal to 3/1

ther fore k is not equal to 6

Answer 2

Answer:

a1/a2 n0t equal to b1/b2

k/3 n0t equal to 3/1

crossmultiply

k n0t equal to 6

Step-by-step explanation: