if ...........solve fast
Attachments:
Answers
Answered by
1
multiplying throughout by abc
we get
a³+b³+c³= (a+b+c)³
∵a+b+c=0
∴(a+b+c)³=0³=0
we get
a³+b³+c³= (a+b+c)³
∵a+b+c=0
∴(a+b+c)³=0³=0
Nightmare1069:
is it correct
ookkkkkk thanks
Similar questions